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	<title>Comments on: How do you fine the area of a triangle given only the hypotenuse and the height or base?</title>
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	<link>http://www.thearealist.com/triangle-area/how-do-you-fine-the-area-of-a-triangle-given-only-the-hypotenuse-and-the-height-or-base</link>
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		<title>By: Mr.Math</title>
		<link>http://www.thearealist.com/triangle-area/how-do-you-fine-the-area-of-a-triangle-given-only-the-hypotenuse-and-the-height-or-base/comment-page-1#comment-1793</link>
		<dc:creator>Mr.Math</dc:creator>
		<pubDate>Tue, 02 Feb 2010 23:31:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-you-fine-the-area-of-a-triangle-given-only-the-hypotenuse-and-the-height-or-base#comment-1793</guid>
		<description>Hello!

A=1/2bh

We need to know the base and height.

If we&#039;re given the base and height, we can multiply it and divide by 2 (:

For your question:

We need to find the base for your question.

We use Pythagorean Theorem:

a^2+b^2=c^2

7^2+b^2=10^2
49+b^2=100
b^2=51
b=√51 
b=7.141428429

The base would be around 7

So now we apply the formula:

A=1/2(7)(7)
A=24.5

Hope this helps!

Sincerely,
Mr.Math

Message me if you need more help.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>Hello!</p>
<p>A=1/2bh</p>
<p>We need to know the base and height.</p>
<p>If we&#8217;re given the base and height, we can multiply it and divide by 2 (:</p>
<p>For your question:</p>
<p>We need to find the base for your question.</p>
<p>We use Pythagorean Theorem:</p>
<p>a^2+b^2=c^2</p>
<p>7^2+b^2=10^2<br />
49+b^2=100<br />
b^2=51<br />
b=√51<br />
b=7.141428429</p>
<p>The base would be around 7</p>
<p>So now we apply the formula:</p>
<p>A=1/2(7)(7)<br />
A=24.5</p>
<p>Hope this helps!</p>
<p>Sincerely,<br />
Mr.Math</p>
<p>Message me if you need more help.<br /><b>References : </b></p>
]]></content:encoded>
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	<item>
		<title>By: I Just Lost the Game</title>
		<link>http://www.thearealist.com/triangle-area/how-do-you-fine-the-area-of-a-triangle-given-only-the-hypotenuse-and-the-height-or-base/comment-page-1#comment-1792</link>
		<dc:creator>I Just Lost the Game</dc:creator>
		<pubDate>Tue, 02 Feb 2010 23:12:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-you-fine-the-area-of-a-triangle-given-only-the-hypotenuse-and-the-height-or-base#comment-1792</guid>
		<description>a² + b² = c²

7² + b² = 10²

49 + b² = 100

b² = 51

b = √51

Now that you know the length of the third side, the area of a triangle formula is A = 1/2bh

A= 1/2 (√51) (7)

A= 3.5(√51)

A = 3.5(7.14142843)

A = 24.9949995, or about 25.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>a² + b² = c²</p>
<p>7² + b² = 10²</p>
<p>49 + b² = 100</p>
<p>b² = 51</p>
<p>b = √51</p>
<p>Now that you know the length of the third side, the area of a triangle formula is A = 1/2bh</p>
<p>A= 1/2 (√51) (7)</p>
<p>A= 3.5(√51)</p>
<p>A = 3.5(7.14142843)</p>
<p>A = 24.9949995, or about 25.<br /><b>References : </b></p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Matt Rogers</title>
		<link>http://www.thearealist.com/triangle-area/how-do-you-fine-the-area-of-a-triangle-given-only-the-hypotenuse-and-the-height-or-base/comment-page-1#comment-1791</link>
		<dc:creator>Matt Rogers</dc:creator>
		<pubDate>Tue, 02 Feb 2010 23:04:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-you-fine-the-area-of-a-triangle-given-only-the-hypotenuse-and-the-height-or-base#comment-1791</guid>
		<description>We need to find the other length of the triangle first.

By pythagoras, b^2 + 7^2 = 10^2

b = sqrt(100 - 49)

b = sqrt(51)

Then area = 0.5 x base x height

= 0.5 x sqrt(51) x 7

= (7/2)sqrt(51) square units, or approx 25 square units of area&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>We need to find the other length of the triangle first.</p>
<p>By pythagoras, b^2 + 7^2 = 10^2</p>
<p>b = sqrt(100 &#8211; 49)</p>
<p>b = sqrt(51)</p>
<p>Then area = 0.5 x base x height</p>
<p>= 0.5 x sqrt(51) x 7</p>
<p>= (7/2)sqrt(51) square units, or approx 25 square units of area<br /><b>References : </b></p>
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