Each angle of the triangle is labeled as follows beginning left to right beginning with base: X,Y,Z. Angle ‘Y’ is a 90 degree angle. The area of the triangle is 36 cm squared. Need to find the length of leg XY. Answers were: A. 6, B. 9, C. 12, D. 18, F. 24. Can anyone please explain in detail? Thanks!
insufficient data….
Express the hypotenuse h of a right triangle with area 25m^2 as a function of it’s perimeter p.
How would I do this? Thank for helping!
Call A=25 the area.
Call a and b the sides (and their length) adjacent to the right triangle.
We have:
1) Area: A = ab/2, so that ab = 2A
2) perimeter: p = a + b + h, so that a+b = p – h
3) pythagoras: h^2 = a^2 + b^2
Now from (2):
(p-h)^2 = (a+b)^2 = a^2 + b^2 + 2ab
= h^2 + 2(2A) = h^2 + 4A, from the values from (1) and (3).
But (p-h)^2 = p^2 + h^2 – 2ph, so that:
p^2 + h^2 – 2ph = h^2 + 4A
p^2 – 2ph = 4A
2ph = p^2 – 4A
h = (p^2 – 4A) / (2p)
with A=25:
h = (p^2 – 100) / (2p)
I’m doing a project on quadratic equations, and the question says, "Graph the length and area of each rectangle (length on the horizontal axis and area on the vertical axis)." I’m pretty sure that since this project is on quadratic equations, I have to graph a quadratic equation concerning the formula above, but I dont know how to create that quadratic equation 
Help!!
Well, my guess is that the length and the area will have a sort of quadratic relationship already, You are graphing, l vs. l*w
This is not really quadratic, because that, strictly, refers to equations where a single variable is raised to the power of 2 – were you graphing squares – area versus the length of a side, then you would have a clear quadratic.
So you really can’t do that – but my wife teaches high school, and she had trouble with kids just plain learning to graph – she would see a class that had issues and she would assign some stuff like this so that they could get more practice.
Microsoft Math allows you to construct graphs quickly and fold them into your documents easily.
I believe mo its just to shady and dead… If anything might be located beneath ground
It is real. You can’t hide 80 acres of land from a satellite. There are tunnels located around Area 51.
Hi, I have 4 or so graphs to calculate the area of. I am willing to redraw them digitally.
Is there any software which will give me a numerical value for the area under the triangle of each graph?
Or the area of each triangle I draw?
Thanks.
http://www.easycalculation.com/area/triangle.php
I’m planning on moving toNorth Carolina in a month and was wondering if someone could tell me what areas/cities are good to live in. I don’t have a job lined up and want to move to a place where (1) the cost of living is reasonable (2) is safe (3) where I can find a job!
I hear that Raleigh is my best bet but I’m not sure what parts of Raleigh are a good match for me. If you know of any other cities in NC that are good, please let me know!!!
Thanks much!
Hi friend
Raleigh is the capital and the second largest city in the state of North Carolina. This is my favorite place to live there are some reasons behind this.
Uptown Raleigh: It is a best place to live and to get job also because this is residential and commercial place. Crabtree Valley Mall is the anchor of the area. That is a safe area also.
House prices are also not so high.
Crime: Average crime in this area is less than U.S. average. So this is safe area also.
Job : This is a commercial area so you can get a job easily.
Best of luck.
So I am given the question. A triangular block of land has been surveyed and pegged out. Calculate the area of the triangle block of land using Trigonometry Please show working aswell
So the triangle looks like this / Left side 36.4m \ Right side 30.3m _ Bottom 48.5. All help appreciated
Awkward.
You have three sides, so you can find an angle using the cosine rule. With that angle you can calculate the height, then area, of the triangle.
a² = b² + c² – 2bc cosA
36.4² = 30.3² + 48.5² – 2(30.3)(48.5)cosA
1324.96 = 918.09 + 2352.25 – 2939.10cosA
-1945.38 = -2939.10cosA
A = inverse cos(0.6618…) = 48.55…
sinA = height of triangle / 30.3
height of triangle = 30.3 * 0.749… = 22.712…
area of triangle = ½ * base * height = ½ (48.5) (22.712…) = 550.783…
The area of your triangle is 551m² (nearest m²)
Okay the premise is that a polygon is inscribed in a circle with radius r. As n increases, the shape of the n-gon gets closer and closer to the circumference of the circle. The limit becomes closer to one.
Now the question is: What can you conclude is the formula for the area of a circle of radius r?
Step-by-step explaination would be greatly appreciated. Thank you in advance!
This was detailed in this question:
http://answers.yahoo.com/question/index?qid=20100623000747AAjNUsa
But you’ll need L’Hospital’s rule from calculus to understand how to take the limit as n→∞
Hope this is helpful. (I saw no need to reinvent the wheel, so to speak.)
What is the formula for area of a nonogon? I know the side lengths and the apothem.
Let me try….
The formula for area of a regular polygon is A = ½ (nR²sin(360°/n)). ¼(ns²cot(180°/n)) and nr²tan(180°/n) where…
n is the number of sides
R is the radius of circumcircle
s is the length of the side
r is the apothem
I can’t seem to find the area of a regular nonagon, but you can try using that formula I gave you.
Anyway… I hope this helps!
~Tsugara
Is this the correct area formula for regular pentagons? If so, what do the "s" and "n" stand for. I will pick the first answerer to help me understand it.
Yes, it is correct, but a more common formula is:
A = (1/2)ap,
where a is the length of the apothem (the distance between the center to the midpoint of one of the side) and p is the perimeter. Since ns = p, where n is the number of sides and s is the length of each side, your formula is equivalent.
I hope this helps!
