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	<title>Comments for Area List</title>
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		<title>Comment on Why does the matrix area formula for a triangle work? by SCAR</title>
		<link>http://www.thearealist.com/area-formula/why-does-the-matrix-area-formula-for-a-triangle-work/comment-page-1#comment-1978</link>
		<dc:creator>SCAR</dc:creator>
		<pubDate>Tue, 09 Mar 2010 08:44:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/why-does-the-matrix-area-formula-for-a-triangle-work#comment-1978</guid>
		<description>It stems from the property that the area of a parallelogram with two vectors as adjacent sides is equal to the determinant of a matrix with those vectors as rows.  For instance, suppose you have a parallelogram with one edge &lt;1,1&gt; and the adjacent edge &lt;0,1&gt;.  If you form the matrix &#039;A&#039;
[ 1 1]
[ 0 1]

and compute the determinant, you get det(A) = 1, which is the area of the parallelogram.  If now you only want the area of the triangle with sides &lt;1,1&gt; and &lt;0,1&gt;, you divide by 2.  Or 1/2*det(A) = area of triangle.

IF you now draw any triangle with three vertices, and draw vectors from the origin to each vertex, you&#039;ll see that each pair of vectors forms a triangle.  Summing the area of these individual triangles (and recognizing that the order of one pair might make &quot;negative area&quot;) gives the area enclosed by the three vertices, when divided by 2.

The matrix you show is a simple way to combine the three separate determinants into one.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>It stems from the property that the area of a parallelogram with two vectors as adjacent sides is equal to the determinant of a matrix with those vectors as rows.  For instance, suppose you have a parallelogram with one edge &lt;1,1&gt; and the adjacent edge &lt;0,1&gt;.  If you form the matrix &#8216;A&#8217;<br />
[ 1 1]<br />
[ 0 1]</p>
<p>and compute the determinant, you get det(A) = 1, which is the area of the parallelogram.  If now you only want the area of the triangle with sides &lt;1,1&gt; and &lt;0,1&gt;, you divide by 2.  Or 1/2*det(A) = area of triangle.</p>
<p>IF you now draw any triangle with three vertices, and draw vectors from the origin to each vertex, you&#8217;ll see that each pair of vectors forms a triangle.  Summing the area of these individual triangles (and recognizing that the order of one pair might make &quot;negative area&quot;) gives the area enclosed by the three vertices, when divided by 2.</p>
<p>The matrix you show is a simple way to combine the three separate determinants into one.<br /><b>References : </b></p>
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		<title>Comment on How do I use Heron&#8217;s Formula to find the area of the triangle? by Mujtaba Y</title>
		<link>http://www.thearealist.com/area-formula/how-do-i-use-herons-formula-to-find-the-area-of-the-triangle/comment-page-1#comment-1974</link>
		<dc:creator>Mujtaba Y</dc:creator>
		<pubDate>Sun, 07 Mar 2010 08:59:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/how-do-i-use-herons-formula-to-find-the-area-of-the-triangle#comment-1974</guid>
		<description>find the length of each side
let the consecutive odd numbers be a=x ,b= x+2, c=x+4
formula for a perimeter {a+b+c=105}

x + (x+2) + (x+4) = 105
x+x+x=99
3x=99
x=33

therefore length of each side is
a=33, b=35, c=37

then just plug this into the herrons formula&#039;s

step one: 
find half the parimeter (set as variable H impling half perimeter)

step two use:
Find area,
area = squareroot (H (H-a) (H-b) (H-c))


just plug in the numbers and u got the answer.... not doing the calculation cuz the best way to understand math is by doing it urself even if u hate it.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>find the length of each side<br />
let the consecutive odd numbers be a=x ,b= x+2, c=x+4<br />
formula for a perimeter {a+b+c=105}</p>
<p>x + (x+2) + (x+4) = 105<br />
x+x+x=99<br />
3x=99<br />
x=33</p>
<p>therefore length of each side is<br />
a=33, b=35, c=37</p>
<p>then just plug this into the herrons formula&#8217;s</p>
<p>step one:<br />
find half the parimeter (set as variable H impling half perimeter)</p>
<p>step two use:<br />
Find area,<br />
area = squareroot (H (H-a) (H-b) (H-c))</p>
<p>just plug in the numbers and u got the answer&#8230;. not doing the calculation cuz the best way to understand math is by doing it urself even if u hate it.<br /><b>References : </b></p>
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		<title>Comment on What is the area formula for a circle? by kingofclubs_uk</title>
		<link>http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2/comment-page-1#comment-1969</link>
		<dc:creator>kingofclubs_uk</dc:creator>
		<pubDate>Fri, 05 Mar 2010 10:12:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2#comment-1969</guid>
		<description>If you can imagine cutting the circle into really thin sectors - so thin that the curve of the circumference is lost - and you then arrange them one pointing up, one pointing down, one pointing up, one pointing down etc..  You will get a rectangle.

The vertical side of the rectangle will be equal to the radius.  The horizontal sides at the top and bottom will total the circumference (2 pi r)

As to find area we multiply horizontal by vertical, we only want the value of one horizontal side.  2 pi r / 2 = pi r.

So area or a circle = pi r x r = pi r^2&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>If you can imagine cutting the circle into really thin sectors &#8211; so thin that the curve of the circumference is lost &#8211; and you then arrange them one pointing up, one pointing down, one pointing up, one pointing down etc..  You will get a rectangle.</p>
<p>The vertical side of the rectangle will be equal to the radius.  The horizontal sides at the top and bottom will total the circumference (2 pi r)</p>
<p>As to find area we multiply horizontal by vertical, we only want the value of one horizontal side.  2 pi r / 2 = pi r.</p>
<p>So area or a circle = pi r x r = pi r^2<br /><b>References : </b></p>
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		<title>Comment on What is the area formula for a circle? by michaelempeigne</title>
		<link>http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2/comment-page-1#comment-1968</link>
		<dc:creator>michaelempeigne</dc:creator>
		<pubDate>Fri, 05 Mar 2010 09:55:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2#comment-1968</guid>
		<description>A = pi*r^2&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;my brain</description>
		<content:encoded><![CDATA[<p>A = pi*r^2<br /><b>References : </b><br />my brain</p>
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		<title>Comment on What is the area formula for a circle? by MR SCM</title>
		<link>http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2/comment-page-1#comment-1967</link>
		<dc:creator>MR SCM</dc:creator>
		<pubDate>Fri, 05 Mar 2010 09:33:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2#comment-1967</guid>
		<description>π r² where r is the radius.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>π r² where r is the radius.<br /><b>References : </b></p>
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		<title>Comment on What is the area formula for a circle? by MS. B</title>
		<link>http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2/comment-page-1#comment-1966</link>
		<dc:creator>MS. B</dc:creator>
		<pubDate>Fri, 05 Mar 2010 09:12:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2#comment-1966</guid>
		<description>A= pi* r^2
The area is equal to pi times the radius squared. If you do not have the radius, use the diameter. The radius is equal to the diameter divided by 2.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>A= pi* r^2<br />
The area is equal to pi times the radius squared. If you do not have the radius, use the diameter. The radius is equal to the diameter divided by 2.<br /><b>References : </b></p>
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		<title>Comment on What is the area formula for a circle? by Retsum</title>
		<link>http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2/comment-page-1#comment-1965</link>
		<dc:creator>Retsum</dc:creator>
		<pubDate>Fri, 05 Mar 2010 09:07:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2#comment-1965</guid>
		<description>pi.r^2&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>pi.r^2<br /><b>References : </b></p>
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		<title>Comment on What is the area formula for a circle? by KC</title>
		<link>http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2/comment-page-1#comment-1964</link>
		<dc:creator>KC</dc:creator>
		<pubDate>Fri, 05 Mar 2010 08:23:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2#comment-1964</guid>
		<description>π r²&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>π r²<br /><b>References : </b></p>
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		<title>Comment on What is the area formula for a circle? by harry m</title>
		<link>http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2/comment-page-1#comment-1963</link>
		<dc:creator>harry m</dc:creator>
		<pubDate>Fri, 05 Mar 2010 07:55:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/area-formula/what-is-the-area-formula-for-a-circle-2#comment-1963</guid>
		<description>What is the area formula for a circle?

= pi * r^2









QED&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>What is the area formula for a circle?</p>
<p>= pi * r^2</p>
<p>QED<br /><b>References : </b></p>
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		<title>Comment on How do you find the area of a triangle using the determinant of a matrix, only working backwards? by Catalina_romania</title>
		<link>http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-a-triangle-using-the-determinant-of-a-matrix-only-working-backwards/comment-page-1#comment-1970</link>
		<dc:creator>Catalina_romania</dc:creator>
		<pubDate>Fri, 05 Mar 2010 07:28:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-a-triangle-using-the-determinant-of-a-matrix-only-working-backwards#comment-1970</guid>
		<description>I hope you&#039;ll understand what i&#039;m going` to write (i&#039;m from Romania, in the last year of high school)
First of all, I would note the determinant of the matrix with D  and the area with A   , to simplify our work. 
The formula of the area is : A=1/2 * &#124; D &#124; 
the determinant looks like that : 
       -5   1   1
          0   2    1       
       -2   x    1          
now, we&#039;ll solve the determinant with the triangle&#039;s formula  =&gt; 
D= -10 + 0 -2 + 4 + 5x  + 0 = -12 + 4 + 5x = 5x - 8 
We know that A = 4  =&gt;  1/2 * &#124; D &#124; = 4  =&gt;  &#124; D &#124; = 8 =&gt; 5x - 8 = 8 =&gt;
x = 16/5 
hope it will help you in some way&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>I hope you&#8217;ll understand what i&#8217;m going` to write (i&#8217;m from Romania, in the last year of high school)<br />
First of all, I would note the determinant of the matrix with D  and the area with A   , to simplify our work.<br />
The formula of the area is : A=1/2 * | D |<br />
the determinant looks like that :<br />
       -5   1   1<br />
          0   2    1<br />
       -2   x    1<br />
now, we&#8217;ll solve the determinant with the triangle&#8217;s formula  =&gt;<br />
D= -10 + 0 -2 + 4 + 5x  + 0 = -12 + 4 + 5x = 5x &#8211; 8<br />
We know that A = 4  =&gt;  1/2 * | D | = 4  =&gt;  | D | = 8 =&gt; 5x &#8211; 8 = 8 =&gt;<br />
x = 16/5<br />
hope it will help you in some way<br /><b>References : </b></p>
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