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what is the area of the circle of intersection of the plane and sphere?

A sphere of radius 9 meters is intersected by a plane passing 7 meters from the sphere’s center. What is the area of the circle of intersection of the plane and sphere? Please use 3.14 for the approximation of pi.

Radius of the circle = ( 9^2 – 7^2)^0.5 = 5.657 m
area = 3.14 * 5.657^2 = 100.485 m^2………………………ans

This entry was posted on Monday, May 3rd, 2010 at 9:48 pm and is filed under circle area. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

3 Responses to “what is the area of the circle of intersection of the plane and sphere?”

  1. Radius of the circle = ( 9^2 – 7^2)^0.5 = 5.657 m
    area = 3.14 * 5.657^2 = 100.485 m^2………………………ans
    References :

  2. Please remove this question. This is the current Problem of the Week for the Columbus State University Math Contest Problem of the Week.
    References :
    http://www.colstate.edu/mathcontest/problem.php?CategoryID=3&LinkID=Current

  3. chinesedude94 on May 4th, 2010 at 3:49 am

    http://wiki.answers.com/Q/How_do_you_calculate_the_cross_section_area_of_a_sphere

    Just use this formula.This is really common sense. i got the answer right but forgot the m^2 so CSU counted it INCORRECT!!! :(
    References :

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