How do you find the area of a circle inscribed in a equilateral triangle?
The only thing you know is the length of a side is 14 cm. PLEASE HELP!
also, could you find the area of the part not included in the circle?
Draw the radius of the circle from the bottom middle of the triangle to the circle’s center. Then draw a line from the circle’s center to the left vertex of the triangle. As you can clearly see, you now have a 30-60-90 triangle with one leg equal to 7 cm.
From the 30-60-90 ratio that s√3:s:2s
s√3=7
s=7√3/(3)=radius
Area of circle=pi*r^2
Area=pi*49*3/9=49pi/3
Draw the radius of the circle from the bottom middle of the triangle to the circle’s center. Then draw a line from the circle’s center to the left vertex of the triangle. As you can clearly see, you now have a 30-60-90 triangle with one leg equal to 7 cm.
From the 30-60-90 ratio that s√3:s:2s
s√3=7
s=7√3/(3)=radius
Area of circle=pi*r^2
Area=pi*49*3/9=49pi/3
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