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	<title>Comments on: How do I find the ratio of the area of circle I and circlle ll ?</title>
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		<title>By: Caiso</title>
		<link>http://www.thearealist.com/circle-area/how-do-i-find-the-ratio-of-the-area-of-circle-i-and-circlle-ll/comment-page-1#comment-1941</link>
		<dc:creator>Caiso</dc:creator>
		<pubDate>Sat, 27 Feb 2010 08:49:59 +0000</pubDate>
		<guid isPermaLink="false">http://www.thearealist.com/circle-area/how-do-i-find-the-ratio-of-the-area-of-circle-i-and-circlle-ll#comment-1941</guid>
		<description>Let&#039;s say circle I has radius of 1 and circle II has a radius of 2. Find the areas:
circle I = π * 1² = π * 1 = π
circle II = π * 2² = π * 4 = 4π

find the ratio between the areas
π / 4π

1/4 or 1:4&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>Let&#8217;s say circle I has radius of 1 and circle II has a radius of 2. Find the areas:<br />
circle I = π * 1² = π * 1 = π<br />
circle II = π * 2² = π * 4 = 4π</p>
<p>find the ratio between the areas<br />
π / 4π</p>
<p>1/4 or 1:4<br /><b>References : </b></p>
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		<title>By: Geezah</title>
		<link>http://www.thearealist.com/circle-area/how-do-i-find-the-ratio-of-the-area-of-circle-i-and-circlle-ll/comment-page-1#comment-1940</link>
		<dc:creator>Geezah</dc:creator>
		<pubDate>Sat, 27 Feb 2010 08:01:59 +0000</pubDate>
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		<description>You know that the area of a circle is A = pi * r^2.  Let&#039;s say the radius of the smaller circle is &quot;x&quot;.  Then the radius of the larger circle is &quot;2x&quot;.  So the ratio of the smaller circle&#039;s area to the bigger circle&#039;s area is pi r^2 : pi (2x)^2, which you can reduce from there.  You should get 1:4.&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>You know that the area of a circle is A = pi * r^2.  Let&#8217;s say the radius of the smaller circle is &quot;x&quot;.  Then the radius of the larger circle is &quot;2x&quot;.  So the ratio of the smaller circle&#8217;s area to the bigger circle&#8217;s area is pi r^2 : pi (2x)^2, which you can reduce from there.  You should get 1:4.<br /><b>References : </b></p>
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