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	<title>Area List &#187; triangle area</title>
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			<item>
		<title>How do you find the area of triangle?</title>
		<link>http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-triangle</link>
		<comments>http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-triangle#comments</comments>
		<pubDate>Tue, 10 Jan 2012 01:34:30 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-triangle</guid>
		<description><![CDATA[I know area of a triangle equals 1/2 base*height.  But is is, Base times Heighf FIRST, then halve it, or is it half of the base first, then times the height?
That statement was a bit confusing, so here&#8217;s a second one in case you don&#8217;t understand the first one:
When finding the area of a [...]]]></description>
			<content:encoded><![CDATA[<p>I know area of a triangle equals 1/2 base*height.  But is is, Base times Heighf FIRST, then halve it, or is it half of the base first, then times the height?</p>
<p>That statement was a bit confusing, so here&#8217;s a second one in case you don&#8217;t understand the first one:<br />
When finding the area of a triangle, do we divide the product of the base and height FIRST?  Or do we calculate half of the base first, then multiply it by the height?</p>
<p>Thanks in advanced!<br />
<br />It doesn&#8217;t matter what you do first. You can multiply in any order. For instance, let&#8217;s say our base is 5 and our height is 2. Let&#8217;s look at it done every way:</p>
<p>5&#215;2= 10<br />
10x (1/2)= 5</p>
<p>2x (1/2)= 1<br />
1&#215;5= 5</p>
<p>5x (1/2)= 2.5<br />
2.5 x 2= 5</p>
<p>Regardless of what you multiply first, you will always end up with 5.</p>
]]></content:encoded>
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		</item>
		<item>
		<title>How to find Length of the base of a triangle if Area= 36 cm(sq&#8217;d) &amp; base has a 90 degree angle?</title>
		<link>http://www.thearealist.com/triangle-area/how-to-find-length-of-the-base-of-a-triangle-if-area-36-cmsqd-base-has-a-90-degree-angle</link>
		<comments>http://www.thearealist.com/triangle-area/how-to-find-length-of-the-base-of-a-triangle-if-area-36-cmsqd-base-has-a-90-degree-angle#comments</comments>
		<pubDate>Thu, 15 Sep 2011 08:41:08 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-to-find-length-of-the-base-of-a-triangle-if-area-36-cmsqd-base-has-a-90-degree-angle</guid>
		<description><![CDATA[Each angle of the triangle is labeled as follows beginning left to right beginning with base: X,Y,Z. Angle &#8216;Y&#8217; is a 90 degree angle. The area of the triangle is 36 cm squared. Need to find the length of leg XY. Answers were: A. 6, B. 9, C. 12, D. 18, F. 24. Can anyone [...]]]></description>
			<content:encoded><![CDATA[<p>Each angle of the triangle is labeled as follows beginning left to right beginning with base: X,Y,Z. Angle &#8216;Y&#8217; is a 90 degree angle. The area of the triangle is 36 cm squared. Need to find the length of leg XY. Answers were: A. 6, B. 9, C. 12, D. 18, F. 24. Can anyone please explain in detail? Thanks!<br />
<br />insufficient data&#8230;.</p>
]]></content:encoded>
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		<slash:comments>3</slash:comments>
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		<item>
		<title>Express the hypotenuse h of a right triangle given the area as a function of the perimeter?</title>
		<link>http://www.thearealist.com/triangle-area/express-the-hypotenuse-h-of-a-right-triangle-given-the-area-as-a-function-of-the-perimeter</link>
		<comments>http://www.thearealist.com/triangle-area/express-the-hypotenuse-h-of-a-right-triangle-given-the-area-as-a-function-of-the-perimeter#comments</comments>
		<pubDate>Tue, 13 Sep 2011 00:31:31 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/express-the-hypotenuse-h-of-a-right-triangle-given-the-area-as-a-function-of-the-perimeter</guid>
		<description><![CDATA[Express the hypotenuse h of a right triangle with area 25m^2 as a function of it&#8217;s perimeter p.
How would I do this? Thank for helping!
Call A=25 the area.
Call a and b the sides (and their length) adjacent to the right triangle.
We have:
1) Area: A = ab/2, so that ab = 2A
2) perimeter: p = a [...]]]></description>
			<content:encoded><![CDATA[<p>Express the hypotenuse h of a right triangle with area 25m^2 as a function of it&#8217;s perimeter p.</p>
<p>How would I do this? Thank for helping!<br />
<br />Call A=25 the area.<br />
Call a and b the sides (and their length) adjacent to the right triangle.</p>
<p>We have:<br />
1) Area: A = ab/2, so that ab = 2A<br />
2) perimeter: p = a + b + h, so that a+b = p &#8211; h<br />
3) pythagoras: h^2 = a^2 + b^2</p>
<p>Now from (2):<br />
(p-h)^2 = (a+b)^2 = a^2 + b^2 + 2ab<br />
 = h^2 + 2(2A) = h^2 + 4A, from the values from (1) and (3).</p>
<p>But (p-h)^2 = p^2 + h^2 &#8211; 2ph, so that:<br />
p^2 + h^2 &#8211; 2ph = h^2 + 4A<br />
p^2 &#8211; 2ph = 4A<br />
2ph = p^2 &#8211; 4A<br />
h = (p^2 &#8211; 4A) / (2p)</p>
<p>with A=25:<br />
h = (p^2 &#8211; 100) / (2p)</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Software which will calculate the area under a graph? Or triangle area?</title>
		<link>http://www.thearealist.com/triangle-area/software-which-will-calculate-the-area-under-a-graph-or-triangle-area</link>
		<comments>http://www.thearealist.com/triangle-area/software-which-will-calculate-the-area-under-a-graph-or-triangle-area#comments</comments>
		<pubDate>Sat, 03 Sep 2011 11:10:00 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

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		<description><![CDATA[Hi, I have 4 or so graphs to calculate the area of. I am willing to redraw them digitally. 
Is there any software which will give me a numerical value for the area under the triangle of each graph? 
Or the area of each triangle I draw?
Thanks.
http://www.easycalculation.com/area/triangle.php
]]></description>
			<content:encoded><![CDATA[<p>Hi, I have 4 or so graphs to calculate the area of. I am willing to redraw them digitally. </p>
<p>Is there any software which will give me a numerical value for the area under the triangle of each graph? </p>
<p>Or the area of each triangle I draw?</p>
<p>Thanks.<br />
<br />http://www.easycalculation.com/area/triangle.php</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Someone please help me with confused Trig Triangle Area question?</title>
		<link>http://www.thearealist.com/triangle-area/someone-please-help-me-with-confused-trig-triangle-area-question</link>
		<comments>http://www.thearealist.com/triangle-area/someone-please-help-me-with-confused-trig-triangle-area-question#comments</comments>
		<pubDate>Sun, 28 Aug 2011 00:58:06 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/someone-please-help-me-with-confused-trig-triangle-area-question</guid>
		<description><![CDATA[So I am given the question. A triangular block of land has been surveyed and pegged out. Calculate the area of the triangle block of land using Trigonometry  Please show working aswell
So the triangle looks like this / Left side 36.4m \ Right side 30.3m _ Bottom 48.5. All help appreciated
Awkward.
You have three sides, [...]]]></description>
			<content:encoded><![CDATA[<p>So I am given the question. A triangular block of land has been surveyed and pegged out. Calculate the area of the triangle block of land using Trigonometry  Please show working aswell</p>
<p>So the triangle looks like this / Left side 36.4m \ Right side 30.3m _ Bottom 48.5. All help appreciated<br />
<br />Awkward.</p>
<p>You have three sides, so you can find an angle using the cosine rule. With that angle you can calculate the height, then area, of the triangle.</p>
<p>a² = b² + c² &#8211; 2bc cosA<br />
36.4² = 30.3² + 48.5² &#8211; 2(30.3)(48.5)cosA<br />
1324.96 = 918.09 + 2352.25 &#8211; 2939.10cosA<br />
-1945.38 = -2939.10cosA<br />
A = inverse cos(0.6618&#8230;) = 48.55&#8230;</p>
<p>sinA = height of triangle / 30.3<br />
height of triangle = 30.3 * 0.749&#8230; = 22.712&#8230;</p>
<p>area of triangle = ½ * base * height = ½ (48.5) (22.712&#8230;) = 550.783&#8230;</p>
<p>The area of your triangle is 551m² (nearest m²)</p>
]]></content:encoded>
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		</item>
		<item>
		<title>What is the area or perimeter of a triangle whose area and perimeter have the same numerical value?</title>
		<link>http://www.thearealist.com/triangle-area/what-is-the-area-or-perimeter-of-a-triangle-whose-area-and-perimeter-have-the-same-numerical-value</link>
		<comments>http://www.thearealist.com/triangle-area/what-is-the-area-or-perimeter-of-a-triangle-whose-area-and-perimeter-have-the-same-numerical-value#comments</comments>
		<pubDate>Tue, 04 Jan 2011 02:42:43 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/what-is-the-area-or-perimeter-of-a-triangle-whose-area-and-perimeter-have-the-same-numerical-value</guid>
		<description><![CDATA[What is the area or perimeter of a triangle whose area and perimeter have the same numerical value and this value is a minimum with angles 44, 61 and 75 (all degree measures)? Give solution to 8 decimal places.
Max please check the last digit.
21.90390137
]]></description>
			<content:encoded><![CDATA[<p>What is the area or perimeter of a triangle whose area and perimeter have the same numerical value and this value is a minimum with angles 44, 61 and 75 (all degree measures)? Give solution to 8 decimal places.<br />
Max please check the last digit.<br />
<br />21.90390137</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Do centroid divides any triangle area in three equal areas ?</title>
		<link>http://www.thearealist.com/triangle-area/do-centroid-divides-any-triangle-area-in-three-equal-areas</link>
		<comments>http://www.thearealist.com/triangle-area/do-centroid-divides-any-triangle-area-in-three-equal-areas#comments</comments>
		<pubDate>Wed, 08 Dec 2010 20:52:10 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/do-centroid-divides-any-triangle-area-in-three-equal-areas</guid>
		<description><![CDATA[if yes prove it and if no then which point of triangle do this.
Thanks
Hey venkat R
Is this true for all types of Triangle ?
When the centroid is joined to the vertices of  its triangle, it is true that the centroid divides the triangle into three equal areas.  Proof:  Let ABC be the [...]]]></description>
			<content:encoded><![CDATA[<p>if yes prove it and if no then which point of triangle do this.<br />
Thanks<br />
Hey venkat R<br />
Is this true for all types of Triangle ?<br />
<br />When the centroid is joined to the vertices of  its triangle, it is true that the centroid divides the triangle into three equal areas.  Proof:  Let ABC be the triangle and O the centroid. Let AO produced meet BC in D. The Area of the triangles ABD = Area of triangle ACD. ( Reason BD=CD and same altitude. Area = 1/2*base*altitude) For the same reason Area OBD = Area OCD. Subtracting i.e </p>
<p>Area ABD &#8211; Area OBD = Area ACD &#8211; Area OCD  which implies Area AOB = Area AOC. Similar proof leads to Area AOC = Area BOC.  Therefore Area AOB = Area AOC = Area BOC. That meand the centroid divides any triangle into three equal areas</p>
<p>for picture click  http://i26.tinypic.com/2r47xtz.gif</p>
]]></content:encoded>
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		<item>
		<title>I have three linear equations &amp; they form a triangle, how do i find the triangles area?</title>
		<link>http://www.thearealist.com/triangle-area/i-have-three-linear-equations-they-form-a-triangle-how-do-i-find-the-triangles-area</link>
		<comments>http://www.thearealist.com/triangle-area/i-have-three-linear-equations-they-form-a-triangle-how-do-i-find-the-triangles-area#comments</comments>
		<pubDate>Tue, 30 Nov 2010 01:18:43 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/i-have-three-linear-equations-they-form-a-triangle-how-do-i-find-the-triangles-area</guid>
		<description><![CDATA[I also have the intercept points.
I have to use the information above (equations and intercepts) to find the area.
Help please!
The equations are y=2x+2, y= -x+5 and y=1/2x-1
the intercepts are (1,4) (-2,-2) and (4,1)
First take the distance between each intercept:
d = sqrt((second x &#8211; first x) ^2 + (second y &#8211; first y)^2)
So the distance between [...]]]></description>
			<content:encoded><![CDATA[<p>I also have the intercept points.<br />
I have to use the information above (equations and intercepts) to find the area.<br />
Help please!<br />
The equations are y=2x+2, y= -x+5 and y=1/2x-1<br />
the intercepts are (1,4) (-2,-2) and (4,1)<br />
<br />First take the distance between each intercept:<br />
d = sqrt((second x &#8211; first x) ^2 + (second y &#8211; first y)^2)</p>
<p>So the distance between (1,4) and (-2,-2) would be:<br />
sqrt((1+2)^2 + (4+2)^2)<br />
sqrt(45)</p>
<p>You get a triangle with sides:<br />
sqrt(45), sqrt(18), and sqrt(45), and since it has two sides that are equal it&#8217;s an Isosceles Triangle.</p>
<p>To make things easier (slightly), I&#8217;m just going to use the area formula for an Isosceles Triangle:<br />
A = (1/2)*base^2*sqrt((side^2/base^2) &#8211; (1/4)<br />
A = (1/2)*sqrt(18)^2*sqrt((sqrt(45)^2/sqrt(18)^2) &#8211; (1/4))<br />
A = (1/2)*18*sqrt((45/18) &#8211; (1/4))<br />
A = 9*sqrt(1.1)</p>
<p>Please note that this answer is only correct if the intercepts you gave are correct (I didn&#8217;t check them) as it needs the triangle to have two equal sides.</p>
]]></content:encoded>
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		<item>
		<title>How to find the sides of a triangle given the area and 3 angles?</title>
		<link>http://www.thearealist.com/triangle-area/how-to-find-the-sides-of-a-triangle-given-the-area-and-3-angles</link>
		<comments>http://www.thearealist.com/triangle-area/how-to-find-the-sides-of-a-triangle-given-the-area-and-3-angles#comments</comments>
		<pubDate>Wed, 10 Nov 2010 10:01:33 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

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		<description><![CDATA[An isosceles triangle has an area of 24 cm2, and the angle between the two equal sides is
5pi/6. What is the length of the two equal sides?
The length of the two equal sides is approximately equal to 23 cm&#8230;.
Too much working out&#8230;.
]]></description>
			<content:encoded><![CDATA[<p>An isosceles triangle has an area of 24 cm2, and the angle between the two equal sides is<br />
5pi/6. What is the length of the two equal sides?<br />
<br />The length of the two equal sides is approximately equal to 23 cm&#8230;.<br />
Too much working out&#8230;.</p>
]]></content:encoded>
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		<item>
		<title>Really need a Calc expert! A rectangle (positioned askew) inscribed in a right triangle, maximize area?</title>
		<link>http://www.thearealist.com/triangle-area/really-need-a-calc-expert-a-rectangle-positioned-askew-inscribed-in-a-right-triangle-maximize-area</link>
		<comments>http://www.thearealist.com/triangle-area/really-need-a-calc-expert-a-rectangle-positioned-askew-inscribed-in-a-right-triangle-maximize-area#comments</comments>
		<pubDate>Tue, 06 Jul 2010 08:29:42 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

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		<description><![CDATA[A rectangle is to be inscribed in a right triangle having sides of length 6(ground leg), 8 (standing leg), and 10 in (hypotenuse). Find the dimensions of the rectangle with the greatest area assuming the rectangle is positioned with one side running directly on the hypotenuse (so like tipped up on one side). Need explanation! [...]]]></description>
			<content:encoded><![CDATA[<p>A rectangle is to be inscribed in a right triangle having sides of length 6(ground leg), 8 (standing leg), and 10 in (hypotenuse). Find the dimensions of the rectangle with the greatest area assuming the rectangle is positioned with one side running directly on the hypotenuse (so like tipped up on one side). Need explanation! But any ideas will help.<br />
<br />This one is hard to explain in print. Let x be the side of the rectangle on the hypotenuse and y be the other side. There is a triangle formed at the right angle of the original which is similar to the original.<br />
So x is to 10 as z is to 8:  x/10 = z/8<br />
and z = 4/5 x<br />
The upper part of that leg would be 8 &#8211; 4/5 x</p>
<p>The triangle at the top is also similar:<br />
So y is to 6 as (8 &#8211; 4/5 x) is to 10:  y/6 = (8-4/5 x)/10<br />
and y = 3/5 (8- 4/5 x) = 24/5 &#8211; 12/25 x</p>
<p>Now area = xy<br />
Deriv = 0 and solve</p>
]]></content:encoded>
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