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<channel>
	<title>Area List &#187; triangle area</title>
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			<item>
		<title>Really need a Calc expert! A rectangle (positioned askew) inscribed in a right triangle, maximize area?</title>
		<link>http://www.thearealist.com/triangle-area/really-need-a-calc-expert-a-rectangle-positioned-askew-inscribed-in-a-right-triangle-maximize-area</link>
		<comments>http://www.thearealist.com/triangle-area/really-need-a-calc-expert-a-rectangle-positioned-askew-inscribed-in-a-right-triangle-maximize-area#comments</comments>
		<pubDate>Tue, 06 Jul 2010 08:29:42 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/really-need-a-calc-expert-a-rectangle-positioned-askew-inscribed-in-a-right-triangle-maximize-area</guid>
		<description><![CDATA[A rectangle is to be inscribed in a right triangle having sides of length 6(ground leg), 8 (standing leg), and 10 in (hypotenuse). Find the dimensions of the rectangle with the greatest area assuming the rectangle is positioned with one side running directly on the hypotenuse (so like tipped up on one side). Need explanation! [...]]]></description>
			<content:encoded><![CDATA[<p>A rectangle is to be inscribed in a right triangle having sides of length 6(ground leg), 8 (standing leg), and 10 in (hypotenuse). Find the dimensions of the rectangle with the greatest area assuming the rectangle is positioned with one side running directly on the hypotenuse (so like tipped up on one side). Need explanation! But any ideas will help.<br />
<br />This one is hard to explain in print. Let x be the side of the rectangle on the hypotenuse and y be the other side. There is a triangle formed at the right angle of the original which is similar to the original.<br />
So x is to 10 as z is to 8:  x/10 = z/8<br />
and z = 4/5 x<br />
The upper part of that leg would be 8 &#8211; 4/5 x</p>
<p>The triangle at the top is also similar:<br />
So y is to 6 as (8 &#8211; 4/5 x) is to 10:  y/6 = (8-4/5 x)/10<br />
and y = 3/5 (8- 4/5 x) = 24/5 &#8211; 12/25 x</p>
<p>Now area = xy<br />
Deriv = 0 and solve</p>
]]></content:encoded>
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		<slash:comments>2</slash:comments>
		</item>
		<item>
		<title>What are the best July 4 fireworks shows in the Triangle Area?</title>
		<link>http://www.thearealist.com/triangle-area/what-are-the-best-july-4-fireworks-shows-in-the-triangle-area</link>
		<comments>http://www.thearealist.com/triangle-area/what-are-the-best-july-4-fireworks-shows-in-the-triangle-area#comments</comments>
		<pubDate>Wed, 30 Jun 2010 16:23:51 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

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		<description><![CDATA[What are the best fireworks shows that occur on 4th of July in or around the Triangle Area in North Carolina?
CHECK YOUR LOCAL PAPER
]]></description>
			<content:encoded><![CDATA[<p>What are the best fireworks shows that occur on 4th of July in or around the Triangle Area in North Carolina?<br />
<br />CHECK YOUR LOCAL PAPER</p>
]]></content:encoded>
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		</item>
		<item>
		<title>How do i find the area of triangle knowing 3 sides?</title>
		<link>http://www.thearealist.com/triangle-area/how-do-i-find-the-area-of-triangle-knowing-3-sides-2</link>
		<comments>http://www.thearealist.com/triangle-area/how-do-i-find-the-area-of-triangle-knowing-3-sides-2#comments</comments>
		<pubDate>Mon, 28 Jun 2010 20:39:07 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-i-find-the-area-of-triangle-knowing-3-sides-2</guid>
		<description><![CDATA[I know you have to take the sum of 3 sides first then use that to subtract each what you do next??
4. What is the area of triangle ABC if a=8,b=10, and c=15?
5. What is the area of traingle ABC if a=42, b=17, and c=25?
It&#8217;s called Heron&#8217;s formula:
http://www.mathopenref.com/heronsformula.html
What is the area of triangle ABC if [...]]]></description>
			<content:encoded><![CDATA[<p>I know you have to take the sum of 3 sides first then use that to subtract each what you do next??<br />
4. What is the area of triangle ABC if a=8,b=10, and c=15?<br />
5. What is the area of traingle ABC if a=42, b=17, and c=25?<br />
<br />It&#8217;s called Heron&#8217;s formula:</p>
<p>http://www.mathopenref.com/heronsformula.html</p>
<p>What is the area of triangle ABC if a=8,b=10, and c=15?<br />
SSS:  SIDES: p= 8 , q= 10 , r= 15,  area: 36.97888</p>
<p>What is the area of traingle ABC if a=42, b=17, and c=25?<br />
SSS:  SIDES: p= 42 , q= 17 , r= 25  Invalid combination of sides.</p>
<p>q+r = p<br />
Area is zero.</p>
]]></content:encoded>
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		</item>
		<item>
		<title>how do i find the area of triangle knowing 3 sides?</title>
		<link>http://www.thearealist.com/triangle-area/how-do-i-find-the-area-of-triangle-knowing-3-sides</link>
		<comments>http://www.thearealist.com/triangle-area/how-do-i-find-the-area-of-triangle-knowing-3-sides#comments</comments>
		<pubDate>Fri, 25 Jun 2010 18:31:38 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-i-find-the-area-of-triangle-knowing-3-sides</guid>
		<description><![CDATA[I know you have to take the sum of 3 sides first then use that to subtract each what you do next??
4. What is the area of triangle ABC if a=8,b=10, and c=15?
5. What is the area of traingle ABC if a=42, b=17, and c=25?
It&#8217;s called Heron&#8217;s formula:
http://www.mathopenref.com/heronsformula…
What is the area of triangle ABC if [...]]]></description>
			<content:encoded><![CDATA[<p>I know you have to take the sum of 3 sides first then use that to subtract each what you do next??<br />
4. What is the area of triangle ABC if a=8,b=10, and c=15?<br />
5. What is the area of traingle ABC if a=42, b=17, and c=25?<br />
<br />It&#8217;s called Heron&#8217;s formula:</p>
<p>http://www.mathopenref.com/heronsformula…</p>
<p>What is the area of triangle ABC if a=8,b=10, and c=15?<br />
SSS: SIDES: p= 8 , q= 10 , r= 15, area: 36.97888</p>
<p>What is the area of traingle ABC if a=42, b=17, and c=25?<br />
SSS: SIDES: p= 42 , q= 17 , r= 25 Invalid combination of sides.</p>
<p>q+r = p<br />
Area is zero.</p>
]]></content:encoded>
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		</item>
		<item>
		<title>How to find area and side length of triangle?</title>
		<link>http://www.thearealist.com/triangle-area/how-to-find-area-and-side-length-of-triangle</link>
		<comments>http://www.thearealist.com/triangle-area/how-to-find-area-and-side-length-of-triangle#comments</comments>
		<pubDate>Mon, 26 Apr 2010 05:38:48 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

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		<description><![CDATA[2 questions i cant figure out ?
1. Find the side length of an equilateral triangle with an area of 36sqrt3
2. Find the perimeter of an equilateral triangle with a height of 7sqrt3.
please explain or give formulas or even a website that explains? thanks
The area of a triangle is bh/2.  An equilateral triangle has some [...]]]></description>
			<content:encoded><![CDATA[<p>2 questions i cant figure out ?</p>
<p>1. Find the side length of an equilateral triangle with an area of 36sqrt3</p>
<p>2. Find the perimeter of an equilateral triangle with a height of 7sqrt3.</p>
<p>please explain or give formulas or even a website that explains? thanks<br />
<br />The area of a triangle is bh/2.  An equilateral triangle has some special properties that help us out.<br />
Slice the equilateral triangle down the middle vertically, producing 2 30/60/90 degree triangles.   If the base of the 30/60/90 triangle is x, then the hypotenuse (the original side of the triangle) is 2x, and the height is Sqrt(3)x.  so the area of the equilateral  triangle is the same as both of the 30/60/90 triangles, or x^2 Sqrt(3) where x is half the side of the equilateral triangle.</p>
<p>So x = 6 and the side of the equilateral triangle is 12.</p>
<p>2) If the height is 7sqrt(3) then teh base of teh 30/60/90 is 7, and the side is 14.  3 x 14 = 42</p>
<p>Grandpa</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Working out side of a triangle using given 2 sides and area?</title>
		<link>http://www.thearealist.com/triangle-area/working-out-side-of-a-triangle-using-given-2-sides-and-area</link>
		<comments>http://www.thearealist.com/triangle-area/working-out-side-of-a-triangle-using-given-2-sides-and-area#comments</comments>
		<pubDate>Mon, 29 Mar 2010 00:01:47 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/working-out-side-of-a-triangle-using-given-2-sides-and-area</guid>
		<description><![CDATA[I have been given the triangle ABC.
AB=3.2cm
BC=8.4cm
The area of triangle ABC is 10cm²
There are no right angles.
Basically, I need to find the perimeter, so I need the missing side first.
Any ideas on how to do this would be greatly appreciated, thank you.
One standard formula for the area of a triangle  is
Area = 1/2 a.c [...]]]></description>
			<content:encoded><![CDATA[<p>I have been given the triangle ABC.<br />
AB=3.2cm<br />
BC=8.4cm<br />
The area of triangle ABC is 10cm²<br />
There are no right angles.</p>
<p>Basically, I need to find the perimeter, so I need the missing side first.<br />
Any ideas on how to do this would be greatly appreciated, thank you.<br />
<br />One standard formula for the area of a triangle  is<br />
Area = 1/2 a.c sinB<br />
Here you are given the area,   a  and  c, i.e. the area, AB  and  BC<br />
So you have:   10  =  3.2  x 8.4  x sinB<br />
sinB  =  0.3720<br />
You now have 2 sides and the included angle.<br />
Use cosine formula to get side b.<br />
b^2 = a^2 + c^2 &#8211; 2a c cosB<br />
cosB = 0.9287  (convert from from sinB)<br />
b^2 = 8.4^2 + 3.2^2 &#8211; 2  x  8.4  x 3.2 x 0.9287<br />
b^2 = 70.56 + 10.24   &#8211;  49.93<br />
b^2 =  30.87<br />
b =  5.55<br />
So the perimeter =  sum of the 3 sides = 3.2 + 8.4 + 5.55 = 17.15<br />
I am not claiming this is the shortest method.</p>
]]></content:encoded>
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		</item>
		<item>
		<title>What is the relationship between angles in a triangle and the resulting area of the triangle?</title>
		<link>http://www.thearealist.com/triangle-area/what-is-the-relationship-between-angles-in-a-triangle-and-the-resulting-area-of-the-triangle</link>
		<comments>http://www.thearealist.com/triangle-area/what-is-the-relationship-between-angles-in-a-triangle-and-the-resulting-area-of-the-triangle#comments</comments>
		<pubDate>Wed, 17 Mar 2010 01:33:48 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/what-is-the-relationship-between-angles-in-a-triangle-and-the-resulting-area-of-the-triangle</guid>
		<description><![CDATA[1.  How does the size of an angle in a given triangle relate to the Area of the triangle?
2.  How does the sin of an angle relate to the area?
3.  When graphing the area of a triangle against   Sin(theta), a straight line is produced.  What does the slope and [...]]]></description>
			<content:encoded><![CDATA[<p>1.  How does the size of an angle in a given triangle relate to the Area of the triangle?<br />
2.  How does the sin of an angle relate to the area?<br />
3.  When graphing the area of a triangle against   Sin(theta), a straight line is produced.  What does the slope and equation of this line mean?  </p>
<p>Any help greatly appreciated.<br />
Thanks, John.<br />
<br />1)area=1/2a*b*sin(C)  where; a,b,C are lengths &amp;angle of usual tri angle  that is A propotional to c<br />
2) area=1/2a*b*sin(C)<br />
3) 1/2*a*b   area of rectangula triangle</p>
]]></content:encoded>
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		</item>
		<item>
		<title>How do you find the area of a triangle using the determinant of a matrix, only working backwards?</title>
		<link>http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-a-triangle-using-the-determinant-of-a-matrix-only-working-backwards</link>
		<comments>http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-a-triangle-using-the-determinant-of-a-matrix-only-working-backwards#comments</comments>
		<pubDate>Fri, 05 Mar 2010 01:38:49 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/how-do-you-find-the-area-of-a-triangle-using-the-determinant-of-a-matrix-only-working-backwards</guid>
		<description><![CDATA[Find x, such that the triangle has an area of 4.
(-5, 1), (0, 2), (-2, x)
Can someone please help me solve for x using a graphing calculator?
Thanks!
I hope you&#8217;ll understand what i&#8217;m going` to write (i&#8217;m from Romania, in the last year of high school)
First of all, I would note the determinant of the matrix [...]]]></description>
			<content:encoded><![CDATA[<p>Find x, such that the triangle has an area of 4.</p>
<p>(-5, 1), (0, 2), (-2, x)</p>
<p>Can someone please help me solve for x using a graphing calculator?<br />
Thanks!<br />
<br />I hope you&#8217;ll understand what i&#8217;m going` to write (i&#8217;m from Romania, in the last year of high school)<br />
First of all, I would note the determinant of the matrix with D  and the area with A   , to simplify our work.<br />
The formula of the area is : A=1/2 * | D |<br />
the determinant looks like that :<br />
       -5   1   1<br />
          0   2    1<br />
       -2   x    1<br />
now, we&#8217;ll solve the determinant with the triangle&#8217;s formula  =&gt;<br />
D= -10 + 0 -2 + 4 + 5x  + 0 = -12 + 4 + 5x = 5x &#8211; 8<br />
We know that A = 4  =&gt;  1/2 * | D | = 4  =&gt;  | D | = 8 =&gt; 5x &#8211; 8 = 8 =&gt;<br />
x = 16/5<br />
hope it will help you in some way</p>
]]></content:encoded>
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		</item>
		<item>
		<title>Confused with this triangle area problem?</title>
		<link>http://www.thearealist.com/triangle-area/confused-with-this-triangle-area-problem</link>
		<comments>http://www.thearealist.com/triangle-area/confused-with-this-triangle-area-problem#comments</comments>
		<pubDate>Thu, 25 Feb 2010 00:19:04 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

		<guid isPermaLink="false">http://www.thearealist.com/triangle-area/confused-with-this-triangle-area-problem</guid>
		<description><![CDATA[&#34;The sum of the area of two triangles is 120cm^2. The triangles overlap to create another triangle, which is shaded. If 2/3 of the smaller triangle is unshaded, and 8/9 of the larger triangle is unshaded, what is the area of the shaded overlapping triangle?&#34;
I tried to set up a system relating the two, but [...]]]></description>
			<content:encoded><![CDATA[<p>&quot;The sum of the area of two triangles is 120cm^2. The triangles overlap to create another triangle, which is shaded. If 2/3 of the smaller triangle is unshaded, and 8/9 of the larger triangle is unshaded, what is the area of the shaded overlapping triangle?&quot;</p>
<p>I tried to set up a system relating the two, but had two variables in one, and three in the other. Substitution only proved x = x for me. :p</p>
<p>Could someone get me started on the right path?<br />
<br />The part that is overlapping (shaded) is 1/3 of the smaller triangle, and 1/9 of the larger triangle.<br />
S = area of the smaller triangle<br />
L = area of the larger triangle</p>
<p>(1/3)S = (1/9)L<br />
S = (1/3)L</p>
<p>You know that S + L = 120</p>
<p>By substitution, (1/3)L + L = 120<br />
(4/3)L = 120<br />
L = 90<br />
S = 30</p>
<p>(1/3) of 30 = 10<br />
(1/9) of 90 = 10</p>
<p>The overlapping area is 10cm²</p>
]]></content:encoded>
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		</item>
		<item>
		<title>How to find area of triangle  using vertices, and angles?</title>
		<link>http://www.thearealist.com/triangle-area/how-to-find-area-of-triangle-using-vertices-and-angles</link>
		<comments>http://www.thearealist.com/triangle-area/how-to-find-area-of-triangle-using-vertices-and-angles#comments</comments>
		<pubDate>Thu, 18 Feb 2010 22:24:50 +0000</pubDate>
		<dc:creator>admin</dc:creator>
				<category><![CDATA[triangle area]]></category>

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		<description><![CDATA[Let  be the triangle with vertices at P=(3,−2,1), Q=(−5,2,−5) and R=(3,−3,2).
The area of is: 
The angle ∠QPR is _____ degrees
The angle ∠PQR is _____ degrees
The angle ∠PRQ is _____ degrees
14 degrees
23 degrees
97 degrees
]]></description>
			<content:encoded><![CDATA[<p>Let  be the triangle with vertices at P=(3,−2,1), Q=(−5,2,−5) and R=(3,−3,2).</p>
<p>The area of is: </p>
<p>The angle ∠QPR is _____ degrees<br />
The angle ∠PQR is _____ degrees<br />
The angle ∠PRQ is _____ degrees<br />
<br />14 degrees</p>
<p>23 degrees</p>
<p>97 degrees</p>
]]></content:encoded>
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