Area List » area 5 http://www.thearealist.com Fri, 03 Feb 2012 07:36:48 +0000 http://wordpress.org/?v=2.8.4 en hourly 1 How much would the temperature of the nevada desert change if a 2.5 mile area was changed from white to black? http://www.thearealist.com/area-5/how-much-would-the-temperature-of-the-nevada-desert-change-if-a-2-5-mile-area-was-changed-from-white-to-black http://www.thearealist.com/area-5/how-much-would-the-temperature-of-the-nevada-desert-change-if-a-2-5-mile-area-was-changed-from-white-to-black#comments Fri, 25 Jun 2010 18:31:56 +0000 admin http://www.thearealist.com/area-5/how-much-would-the-temperature-of-the-nevada-desert-change-if-a-2-5-mile-area-was-changed-from-white-to-black So – say there was an area of the Nevada Desert that was completely white, and you painted it completely black. How much would the local temperature changeover the next 50 years, and also the next 200 years? Also, how would the entire state of Nevada’s temperature change during those two time frames?

The local temperature of a desert area of 2.5 square miles would absorb more sunlight and would be about 20F warmer just in that region. Given that the entire size of Nevada is 110, 561 square miles a tiny spot of 2.5 square miles would only have the slightest difference in temperature for the entire state of less than 1F.

]]> http://www.thearealist.com/area-5/how-much-would-the-temperature-of-the-nevada-desert-change-if-a-2-5-mile-area-was-changed-from-white-to-black/feed 3 How do u make a square with an area of 5 square units? http://www.thearealist.com/area-5/how-do-u-make-a-square-with-an-area-of-5-square-units http://www.thearealist.com/area-5/how-do-u-make-a-square-with-an-area-of-5-square-units#comments Tue, 11 May 2010 07:05:15 +0000 admin http://www.thearealist.com/area-5/how-do-u-make-a-square-with-an-area-of-5-square-units i need help drawing a square that is equal to 5 square units on a piece of graph paper. please help! pictures or visuals would help too!

a square has four equal sides. A side time a side is the area… so to make a square with an area of 5 the length of each side need to be the square root of 5.

]]> http://www.thearealist.com/area-5/how-do-u-make-a-square-with-an-area-of-5-square-units/feed 1 What is the area of a regular octagon with a side of 6.5 and an apothem 5? http://www.thearealist.com/area-5/what-is-the-area-of-a-regular-octagon-with-a-side-of-6-5-and-an-apothem-5 http://www.thearealist.com/area-5/what-is-the-area-of-a-regular-octagon-with-a-side-of-6-5-and-an-apothem-5#comments Thu, 22 Apr 2010 02:21:58 +0000 admin http://www.thearealist.com/area-5/what-is-the-area-of-a-regular-octagon-with-a-side-of-6-5-and-an-apothem-5 What is the area of a regular octagon with a side of 6.5 and an apothem 5?

use the apothem and the side of 6.5 to find the area of that triangle and times it by 8 since an octagon is 8 triangles put together, thus:

5*6.5*0.5 = 16.25
16.25 * 8 = 130

]]> http://www.thearealist.com/area-5/what-is-the-area-of-a-regular-octagon-with-a-side-of-6-5-and-an-apothem-5/feed 4 The radius and height of a right cylinder are each divided by √5. What is the change in surface area of the cy? http://www.thearealist.com/area-5/the-radius-and-height-of-a-right-cylinder-are-each-divided-by-%e2%88%9a5-what-is-the-change-in-surface-area-of-the-cy http://www.thearealist.com/area-5/the-radius-and-height-of-a-right-cylinder-are-each-divided-by-%e2%88%9a5-what-is-the-change-in-surface-area-of-the-cy#comments Sun, 04 Apr 2010 01:36:26 +0000 admin http://www.thearealist.com/area-5/the-radius-and-height-of-a-right-cylinder-are-each-divided-by-%e2%88%9a5-what-is-the-change-in-surface-area-of-the-cy The radius and height of a right cylinder are each divided by √5. What is the change in surface area of the cylinder?

The ORIGINAL surface area of a cylinder = (2πR² + 2πRH)

The NEW surface area of a cylinder = (2)(π)(R/√5)² + (2)(π)(r/√5)(h/√5)
The NEW surface area of a cylinder = 2πR²/(√5)² + 2πRH/(√5√5)
The NEW surface area of a cylinder = 2πR²/5 + 2πRH/5
The NEW surface area of a cylinder = (2πR² + 2πRH) / 5

So just compare the ORIGINAL equation with the NEW equation.
Compare (2πR² + 2πRH) to (2πR² + 2πRH) / 5.
How are they different?
That will be the answer.

]]> http://www.thearealist.com/area-5/the-radius-and-height-of-a-right-cylinder-are-each-divided-by-%e2%88%9a5-what-is-the-change-in-surface-area-of-the-cy/feed 1 Is it normal to get cramps in your uterus area at 5 weeks pregnant? http://www.thearealist.com/area-5/is-it-normal-to-get-cramps-in-your-uterus-area-at-5-weeks-pregnant http://www.thearealist.com/area-5/is-it-normal-to-get-cramps-in-your-uterus-area-at-5-weeks-pregnant#comments Fri, 02 Apr 2010 03:23:57 +0000 admin http://www.thearealist.com/area-5/is-it-normal-to-get-cramps-in-your-uterus-area-at-5-weeks-pregnant
It can be very normal to get these cramps around this time. It can feel like your getting your period even.
Your uterus expands in such an enormous way in the first couple of weeks that it makes sense that that would hurt a little. As long as these pains are not accompanied by blood loss you don’t have to worry. Just take it easy when it starts to hurt, your body needs time to adjust to al the changes.

BTW, congratulations

]]> http://www.thearealist.com/area-5/is-it-normal-to-get-cramps-in-your-uterus-area-at-5-weeks-pregnant/feed 7 If a square has an area of 5, then what is the length of one side? http://www.thearealist.com/area-5/if-a-square-has-an-area-of-5-then-what-is-the-length-of-one-side http://www.thearealist.com/area-5/if-a-square-has-an-area-of-5-then-what-is-the-length-of-one-side#comments Mon, 29 Mar 2010 00:02:26 +0000 admin http://www.thearealist.com/area-5/if-a-square-has-an-area-of-5-then-what-is-the-length-of-one-side Explain how you got the answer please.

The formula to compute for the area of square is A = s^2; with s being the measure of the side. Hence, to solve for the length of the side given the area;

5 = s^2

s = the square root of 5.

s = 2.236

arnold

]]> http://www.thearealist.com/area-5/if-a-square-has-an-area-of-5-then-what-is-the-length-of-one-side/feed 5 What are causes for a sudden weight gain in a 5 year old? The weight is only in the stomach area.? http://www.thearealist.com/area-5/what-are-causes-for-a-sudden-weight-gain-in-a-5-year-old-the-weight-is-only-in-the-stomach-area http://www.thearealist.com/area-5/what-are-causes-for-a-sudden-weight-gain-in-a-5-year-old-the-weight-is-only-in-the-stomach-area#comments Wed, 17 Feb 2010 00:43:48 +0000 admin http://www.thearealist.com/area-5/what-are-causes-for-a-sudden-weight-gain-in-a-5-year-old-the-weight-is-only-in-the-stomach-area My 5 year old is 51 inches tall and weighs roughly 60 lbs. She has a cute figure except for her belly. It seems like any additional weight gain goes straight to her stomach area. The rest of her body is in proportion to her height. She’s active in school and extracurricular activities as well. Should I be concerned?

I would definately talk to your pediatrician about it on your next visit.

]]> http://www.thearealist.com/area-5/what-are-causes-for-a-sudden-weight-gain-in-a-5-year-old-the-weight-is-only-in-the-stomach-area/feed 3 HElp ASAP The lateral area of a rectangular prism with height of 5 feet is 175 feet squared. What is the p? http://www.thearealist.com/area-5/help-asap-the-lateral-area-of-a-rectangular-prism-with-height-of-5-feet-is-175-feet-squared-what-is-the-p http://www.thearealist.com/area-5/help-asap-the-lateral-area-of-a-rectangular-prism-with-height-of-5-feet-is-175-feet-squared-what-is-the-p#comments Sun, 14 Feb 2010 21:14:21 +0000 admin http://www.thearealist.com/area-5/help-asap-the-lateral-area-of-a-rectangular-prism-with-height-of-5-feet-is-175-feet-squared-what-is-the-p The lateral area of a rectangular prism with height of 5 feet is 175 feet squared. What is the perimeter of the base?

175 = 4 x 5 x b
175/20 = b
b = 8.75

8.75 ^2 = 35

The answer is 35ft.

]]> http://www.thearealist.com/area-5/help-asap-the-lateral-area-of-a-rectangular-prism-with-height-of-5-feet-is-175-feet-squared-what-is-the-p/feed 1 A farmer wants to fence an area of 37.5 million square feet in a rectangular field? http://www.thearealist.com/area-5/a-farmer-wants-to-fence-an-area-of-37-5-million-square-feet-in-a-rectangular-field http://www.thearealist.com/area-5/a-farmer-wants-to-fence-an-area-of-37-5-million-square-feet-in-a-rectangular-field#comments Tue, 09 Feb 2010 14:22:12 +0000 admin http://www.thearealist.com/area-5/a-farmer-wants-to-fence-an-area-of-37-5-million-square-feet-in-a-rectangular-field question continued….and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the cost of the fence? (Give the dimensions in increasing order.)

Let one side be length A and the other B
Total area = A.B = k where k is the constant value 37.5 million

Then B = k/A……………….(i)

The total length of the sides plus the division fencing will be

L = 2A + 2B + A if we let the division fence be parallel to A: it doesn’t matter either way.

So L = 2A + 2k/A + A = 3A + 2k/A …………….. (ii)

Differentiate L with respect to A, to get

L’ = 3 – 2k/(A^2) = 0 for max or min

This gives A^2 = 2k/3 and so A = sqr root of 2k/3

Substitute in (i) to get

B = k/[sqr root of 2k/3] = sqr root of 3k/2 by division and rearrangement.

Now put the value of k in place as 37.5 million and
the length of side A should be 5000 ft and
the length of side B should be 7500 ft and the division fence should be parallel to side A and measure 5000 ft.

Check the second derivative of L, to get

L” = 4k/(A^3) which is positive since k and A are both positive, so we have a minimum.

The total length of wire will be 30,000 feet by substituting values in (ii) and this is the minimum quantity and therefore minimum cost.

OK?

]]> http://www.thearealist.com/area-5/a-farmer-wants-to-fence-an-area-of-37-5-million-square-feet-in-a-rectangular-field/feed 1 how could a knowledge of buoyancy make the work easier when you are clearing rocks from a swimming area (5.3)? http://www.thearealist.com/area-5/how-could-a-knowledge-of-buoyancy-make-the-work-easier-when-you-are-clearing-rocks-from-a-swimming-area-5-3 http://www.thearealist.com/area-5/how-could-a-knowledge-of-buoyancy-make-the-work-easier-when-you-are-clearing-rocks-from-a-swimming-area-5-3#comments Tue, 02 Feb 2010 17:27:26 +0000 admin http://www.thearealist.com/area-5/how-could-a-knowledge-of-buoyancy-make-the-work-easier-when-you-are-clearing-rocks-from-a-swimming-area-5-3 how could a knowledge of buoyancy make the work easier when you are clearing rocks from a swimming area (5.3)

It requires less human force to lift the rocks, because the buoyant force due to water assists you in countering the rocks’ weight.

]]> http://www.thearealist.com/area-5/how-could-a-knowledge-of-buoyancy-make-the-work-easier-when-you-are-clearing-rocks-from-a-swimming-area-5-3/feed 1