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My 5 year old is 51 inches tall and weighs roughly 60 lbs. She has a cute figure except for her belly. It seems like any additional weight gain goes straight to her stomach area. The rest of her body is in proportion to her height. She’s active in school and extracurricular activities as well. Should I be concerned?

I would definately talk to your pediatrician about it on your next visit.

The lateral area of a rectangular prism with height of 5 feet is 175 feet squared. What is the perimeter of the base?

175 = 4 x 5 x b
175/20 = b
b = 8.75

8.75 ^2 = 35

The answer is 35ft.

question continued….and then divide it in half with a fence parallel to one of the sides of the rectangle. How can he do this so as to minimize the cost of the fence? (Give the dimensions in increasing order.)

Let one side be length A and the other B
Total area = A.B = k where k is the constant value 37.5 million

Then B = k/A……………….(i)

The total length of the sides plus the division fencing will be

L = 2A + 2B + A if we let the division fence be parallel to A: it doesn’t matter either way.

So L = 2A + 2k/A + A = 3A + 2k/A …………….. (ii)

Differentiate L with respect to A, to get

L’ = 3 – 2k/(A^2) = 0 for max or min

This gives A^2 = 2k/3 and so A = sqr root of 2k/3

Substitute in (i) to get

B = k/[sqr root of 2k/3] = sqr root of 3k/2 by division and rearrangement.

Now put the value of k in place as 37.5 million and
the length of side A should be 5000 ft and
the length of side B should be 7500 ft and the division fence should be parallel to side A and measure 5000 ft.

Check the second derivative of L, to get

L” = 4k/(A^3) which is positive since k and A are both positive, so we have a minimum.

The total length of wire will be 30,000 feet by substituting values in (ii) and this is the minimum quantity and therefore minimum cost.

OK?

how could a knowledge of buoyancy make the work easier when you are clearing rocks from a swimming area (5.3)

It requires less human force to lift the rocks, because the buoyant force due to water assists you in countering the rocks’ weight.

I,ve even been told that area 5.1 is a cover up story for area 3.1 in colorado. I don’t think it is true but It’s out there

Well, I guess you mean "area 51" instead 5.1 I figure it out just becouse the conspiracy theory you mean. Tha real TRUE is that YES IT EXISTS, there is a military research base area called "area 51", and that area near to roswell town was meant to present the most UFOs activity, but as allways there is few not solid evidence about that, in fact the all the UFO activist, government / alien conspiracy and UFO/alien big bang fashion, was power up by the "roswell incident". It is located in Lincoln County in southern Nevada, even you could saw it satellite via.

please help me
1)find the perimeter and area of a rectangle with width 5 centimeters and lenght 16 centimeters.
2)the width of a rectagular picture is one-half the lenght. the perimeter of the rectangle is 72 inches. find the lenght of the picture.
3)the lenght of a rectangle is three times the width. the perimeter is 49 units. find the lenght.

1) 42 cm
2) 24 in
3) 18 3/8 units
Best answer so far.

Seems like none, but hoping there are.

there aren’t any sorry, not even the surrounding areas. Sorry.

If u wanted to work some where that people are not supose to know about how would u get in?

Get security clearance, so maybe being a US Citizen helps.

Think the rabbits were at a fair or something. They looked animatronic.

hu

is 70 x 32

I live in southeast Michigan and grow all sorts of flowers. Wave Petunias, Calibrocha, Marigolds, Zinnias, Geraniums, Cosmos, Coneflower, Shasta Daisy, Black-Eyed Susans, Impatients, Bleeding Hearts, Stella-Doro Lilly, Butterfly Bush.

Go to a local nursery, they usually don’t sell anything that will not grow in your area. All of the flowers have tags in the pots that tell you if the flowers grow best in shade, part sun or sun. I always go by those tags and have very good luck with my flowers.