What is the formula for area of a pentagon?
just the area of a regular, basic pentagon. thanxxx…..!
i really need the formula for homework. plz help!
what if one side of the heptagon is 17.7 meters long.
what would the area be then?
thanks so much for whoever answered…=>
divide it into 5 triangles so its (5)BH/2
divide it into 5 triangles so its (5)BH/2
References :
here ya go
http://jwilson.coe.uga.edu/EMAT6680/Parsons/MVP6690/Unit/Pentagon/pentagon.html
References :
the area of the triangle x 5
= 1/2 * r * side * 5
References :
Here’s a link to describe the process: http://www.dummies.com/how-to/content/sizing-up-the-area-of-a-polygon.html
Take a look at Figure 3 for an example (see in the link). The information given indicates that the length of one side of the pentagon equals 5 and that the apothem equals 6. Before you can determine the area, you must first calculate the perimeter. If the length of one side of a pentagon is 5, then the perimeter is equal to a side length of 5 multiplied by five sides. So the total perimeter of the pentagon equals 25. If you plug this information into the area formula, you get the following:
A = 1/2 (6)(25)
A = 1/2 (150)
A = 75
So the area of the pentagon in Figure 3, with the given information, is 75 square units.
References :
http://www.dummies.com/how-to/content/sizing-up-the-area-of-a-polygon.html