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The radius and height of a right cylinder are each divided by √5. What is the change in surface area of the cy?

The radius and height of a right cylinder are each divided by √5. What is the change in surface area of the cylinder?

The ORIGINAL surface area of a cylinder = (2πR² + 2πRH)

The NEW surface area of a cylinder = (2)(π)(R/√5)² + (2)(π)(r/√5)(h/√5)
The NEW surface area of a cylinder = 2πR²/(√5)² + 2πRH/(√5√5)
The NEW surface area of a cylinder = 2πR²/5 + 2πRH/5
The NEW surface area of a cylinder = (2πR² + 2πRH) / 5

So just compare the ORIGINAL equation with the NEW equation.
Compare (2πR² + 2πRH) to (2πR² + 2πRH) / 5.
How are they different?
That will be the answer.

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One Response to “The radius and height of a right cylinder are each divided by √5. What is the change in surface area of the cy?”

  1. The ORIGINAL surface area of a cylinder = (2πR² + 2πRH)

    The NEW surface area of a cylinder = (2)(π)(R/√5)² + (2)(π)(r/√5)(h/√5)
    The NEW surface area of a cylinder = 2πR²/(√5)² + 2πRH/(√5√5)
    The NEW surface area of a cylinder = 2πR²/5 + 2πRH/5
    The NEW surface area of a cylinder = (2πR² + 2πRH) / 5

    So just compare the ORIGINAL equation with the NEW equation.
    Compare (2πR² + 2πRH) to (2πR² + 2πRH) / 5.
    How are they different?
    That will be the answer.
    References :

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